WebApr 7, 2024 · 3. This is your solution : public class NewMain { public static void main (String args []) throws ParseException { Scanner s = new Scanner (System.in); char yes; do { System.out.println ("Hi"); yes = s.next ().charAt (0); } while (yes == 'Y'); // if u enter 'Y' the it will continue } } To exit enter any thing other then 'Y'. WebSo, I'm trying to remove a character from a string. I've been using String.Replace and it keeps throwing an exception. The exception says "Cannot convert from String to Char." This is my code: alphabet.Replace(alphabet[alphabetRed], String.Empty); I've already tried Convert.ToChar(String.Empty); and it still throws an exception. Any help would ...
c# - Cannot implicit convert type
http://www.javashuo.com/search/fdlsvd WebAug 15, 2012 · You should not mix C and C++ string functions. Instead of strlen () (a C-style function), use string::size (): for (int i = 0, sLen = s.size (); i < sLen; i++) { cout << s [i]; Sleep (TimeLength); } Here you have a reference with all methods from class string. Share Follow answered Aug 15, 2012 at 14:12 betabandido 18.7k 11 60 75 can my dog have pork
c# - Cannot Convert from string to char - Stack Overflow
WebNov 27, 2015 · A string can be converted to an array of characters by calling the ToCharArray string's method. var characters = stringValue.ToCharArray (); An object of type string [] is not a string, but an array of strings. You cannot convert an array of strings to an array of characters by just calling a method like ToCharArray. WebOct 28, 2024 · The Help page you offered has: String.Split Method (Char[]) Note the square brackets. Excerpt: "Syntax public string[] Split( params char[] separator) Parameters separator Type: System.Char[] A character array that delimits the substrings in this string, an empty array that contains no delimiters, or null." WebFeb 8, 2024 · A string is an array of characters. The start of a string therefore is const char *.Therefore to reference a string, you can use const char * s = "hello";. However if you dereference a const char*, you get a const char.This isn't a string i.e. *s gives you 'h'. In your code *s="hello";, you are saying "assign at the dereferened s the value "hello""."". … can my dog have steak bones