WebWhen Manley runs the particulars of Earth through this equation, he figures out that it’d take about 2.25 x 1032 joules, or 225 million trillion trillion joules. For much larger planets such as Jupiter, you’re going to need about 2 x 1036 joules, which means 2 trillion trillion trillion joules of energy. Web12 jan. 2012 · For Earth, that works out to roughly 224,000,000,000,000,000,000,000,000,000,000 Joules. The Sun takes nearly a WEEK to output that much energy. Think about THAT. To liberate that much... The sun unleashed a powerful Class X1.5 solar flare on March 9, 2011, a solar st… Get the latest science news and learn about scientific breakthroughs and discove… Andy is a content director at Future, and has been working in media and journalis…
The Physics Of Stopping A Meteor With One Punch - Forbes
Web15 apr. 2013 · Unladen and flying at this speed, our swallow would deliver a blow of 6·10 26 Joules to the Earth, about 1,200 times the explosive force of the Chicxulub impact which killed the dinosaurs.... WebOne ton of TNT is equal to 4.2 gigajoules which is more then four billion (4,000,000,000,000) joules (For those not using the Imperial system). One Kiloton is a thousand tons of TNT, one Gigaton is a million tons of TNT and so and and so forth And finally when we come to the more Cosmic Level Feats we shall be using the unit FOE. how far is a pk
Destroying the Universe? How much energy! FanVerse
Web29 apr. 2024 · Humans simply don’t have the firepower to destroy the Earth itself. Technically. ... (30,000 m/s)2 or approximately 3 x 1033 Joules, where m is Earth’s mass and v is its velocity around the Sun. Web25 sep. 2014 · If you’re out to destroy things, you’ve got plenty of options. For a modest-sized clump of matter — like say, planet Earth — there are a number of ways, many of which are completely ... Web11 jul. 2014 · However my equation gives = 6 x 10^41 to destroy a SS and a SN in Jules is 10^44 So THAT would put a super nova at 3 exponents above destroying a SS So, I am assuming that my number of 10^28 tons, is wrong for a supernova, and it is actually more, Since you say 10^28 tons = 10^37 J , so 10^47 J should be 2.4 x 10^34 how far is a park run